Answer:
(A) 140 j/sec (b) 1.26 K
Explanation:
We have given the heat heat flowing into the refrigerator = 40 J/sec
Work done = 40 W
(a) So the heat discharged from the refrigerator [tex]=heat\ flowing\ in\ refrigerator+work\ done=40+100=140j/sec[/tex]
(b) Total heat absorbed =140 j/sec [tex]=140\times 3600=504000j/hour[/tex]
Let the temperature be [tex]\Delta T[/tex]
Heat absorbed per hour =504000 [tex][tex]=400\times 10^3\times \Delta T[/tex]
So [tex]\Delta T=\frac{504000}{400000}=1.26K[/tex]