Answer:
SeCl₆ < SeF₂ < SeO₂
Explanation:
(A) SeO₂
The central atom has 2 bond pairs and 1 lone pair. The molecule is bent shaped which has an angle of 120°.
(B) SeCl₆
The central atom has 6 bond pairs and 0 lone pair. The geometry is octahedral in which the equatorial bonds has an angle of 90° and axial bond has an angle of 90°.
(C) SeF₂
The central atom has 2 bond pairs and 2 lone pairs. The geometry is bent shape which has an angle of approximately 105.5°.
The order is:
SeCl₆ < SeF₂ < SeO₂
The arrangement of the compounds in order of increasing bond angle is SeCl6 < SeF2< SeO2
In all the compounds listed, selenium is the central atom. The bond angle of a compound is predicted in the basis of the valence shell electron pair repulsion theory (VSEPR).
The presence of lone pairs of electrons on the valence shell of the central atom distorts the bond angle in a compound due to greater repulsion of electron pairs. There are is no lone pair on SeCl6 hence it has the predicted bond angle of 90° for species having 6 electron pairs on the outermost shell of the central atom.
For SeO2, there is one lone pair on selenium, the central atom and the molecule is bent at a bond angle slightly less than 120° . For SeF2, there are two lone pairs on selenium the central atom and the molecule is bent at a bond angle of less than 109°.
Hence, the the arrangement of the compounds in order of increasing bond angle is SeCl6 < SeF2< SeO2 .
Learn more: https://brainly.com/question/6179102
