Answer:
(D) 23 Hz
Explanation:
We have given resistance [tex]R=11kohm=11\times 10^3ohm[/tex]
Inductance L =24 H
Capacitance [tex]C=2\mu F=2\times 10^{-6}F[/tex]
We have to maximize the current so we need minimum impedance which is possible in case of resonance
In resonance condition [tex]X_L=X_C[/tex]
[tex]\omega L=\frac{1}{\omega C}[/tex]
[tex]\omega =\frac{1}{\sqrt{LC}}[/tex]
[tex]f =\frac{1}{2\pi \sqrt{LC}}[/tex]
[tex]f =\frac{1}{2\times 3.14\sqrt{24\times 2\times 10^{-6}}}=22.98Hz=23Hz[/tex]
So option (D) is correct option