Question

Solve the system of equations using substitution. y = −2x + 1 4x + 2y = −2

No solution
Infinitely many solutions
(0, −4)
(−4, 0)

Answer 1

Answer:

No solution

Step-by-step explanation:

The first equation is $y=-2x+1$

The second equation is $4x+2y=-2$.

Put the first equation into the second one.

$4x+2(-2x+1)=-2$.

$4x-4x+2=-2$.

$4x-4x=-2-2$.

$0=-4$.

This is not TRUE.

Therefore the system has no solution

Answer 2

Answer: First Option

No solution

Step-by-step explanation:

We have the following system of linear equations

$y = -2x + 1$

$4x + 2y = -2$

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To solve the system of equations using the substitution method, enter the first equation in the second equation as shown below.

$4x + 2(-2x + 1) = -2$

$4x -4x + 2 = -2$

$0= -4$

The variable x is eliminated and 0 is not equal to -4. So the system has no solution