The gravitational acceleration on the Earth's surface is ce of a plan et with the same size, but twice the mass? it be on the A. 16 fect B. 32 fect/second/second C. 64 f D. 128 foet/second second E. 8 feet 18-

Respuesta :

Explanation:

The acceleration due to gravity is on Earth is given by :

[tex]g_e=\dfrac{GM_e}{R^2}[/tex]..............(1)

Where

M is the mass of Earth

R is the radius of Earth

G is the universal gravitational constant

[tex]g_e=32\ ft/s^2[/tex]

The formula for acceleration due to gravity on planet is given by :

[tex]g_p=\dfrac{GM_p}{R_p^2}[/tex]..............(2)

Since, [tex]M_p=2M_e[/tex]

From equation (1) and (2) :

[tex]\dfrac{g_p}{g_e}=\dfrac{M_p}{M_e}[/tex]

[tex]g_p=2\times g_e[/tex]

[tex]g_p=2\times 32\ ft/s^2[/tex]

[tex]g_p=64\ ft/s^2[/tex]

So, the acceleration on the planet is 64 feet per second square. Hence, this is the required solution.

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