Respuesta :
Answer:
Here is code in java.
import java.util.*;
class Solution
{
public static void main (String[] args) throws java.lang.Exception
{
try{
int n;
//scanner class object to read input
Scanner scnr=new Scanner(System.in);
System.out.print("please enter the number:");
// read the input from user
n=scnr.nextInt();
// call the function with argument n
System.out.println(hasOne(n));
}catch(Exception ex){
return;}
}
// method to find "1" in the input number
public static Boolean hasOne(int num)
{
int r;
boolean flag=false;
r=num%10;
while(num>0)
{
//if remainder is 1 then flag will be true
if(r==1)
{
flag=true;
break;
}
// if the remainder is not '1' then it discard the digit
num=num/10;
r=num%10;
}
// returning the value
return flag;
}
}
Explanation:
Create a scanner class object "scnr" to read input.Call the function hasOne()
with parameter "n".In the hasOne(),find the remainder and check if it is equal to 1 or not.if it is equal to 1 then set the flag "true" otherwise discard that digit
as "num=num/10".Repeat this until "num>0".This function will return a boolean value base on the presence of "1" in the number.
Output:
please enter the number:10
true
please enter the number:22
false
