Question

Two adjoining plane mirrors are separated by an angle of 100°. Light is incident on the first mirror at an angle of 70°. The light reflects toward the second mirror and is then reflected from it. At what angle is the light reflected from the second mirror?

Answer 1

Answer:

The angle is the light reflected from the second mirror is 30°

Explanation:

Given that,

Angle between mirrors = 100°

Angle of incident = 70°

We know that,

The incident angle is equal to the reflected angle.

We need to calculate the angle BCA

According to figure,

In $\Delta ABC$,

$\angle ABC+\angle BCA+\angle C=180$

Put the value into the formula

$20+100+\angle BCA=180$

$\angle BCA = 60$

We need to calculate the angle is the light reflected from the second mirror

Using relation of incident and reflection

$i+\angle BCA=90$

$i=90-60=30^{\circ}$

We know that, i = r

So, i=r=30°

Hence, The angle is the light reflected from the second mirror is 30°

Answer 2

Answer:

The angle is the light reflected from the second mirror is 30°

Explanation:

Given that,

Angle between mirrors = 100°

Angle of incident = 70°

We know that,

The incident angle is equal to the reflected angle.

We need to calculate the angle BCA

According to figure,

In ,

Put the value into the formula

We need to calculate the angle is the light reflected from the second mirror

Using relation of incident and reflection

We know that, i = r

So, i=r=30°

Hence, The angle is the light reflected from the second mirror is 30°

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