Answer:
(A) 31.22 ohm (B) 0.5765 A (C)0.8152 A (D) yes
Explanation:
We have given voltage V =18 volt
Frequency f=60 Hz
Capacitance [tex]C=85\mu F=80\times 10^{-6}F[/tex]
(A) Capacitive reactance [tex]X_C=\frac{1}{\omega C}=\frac{1}{2\pi fC}=\frac{1}{2\times 3.14\times 60\times 85\times 10^{-6}}=31.22ohm[/tex]
(B) Rms current [tex]i=\frac{V}{X_C}=\frac{18}{31.22}=0.5765A[/tex]
(C) Maximum current [tex]i_m=\sqrt{2}i_{rms}=1.414\times 0.5765=0.8152A[/tex]
(D) We know that charge Q=current ×time , so from the relation we can see that if current will be maximum then charge will also be maximum