Hey!
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We know that (a = -3), (b = 2), (c = 5), and (d = -4).
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Solution #1:
[tex]=\frac{a-4b}{3c+2d}[/tex]
[tex]=\frac{(-3) - 4(2)}{3(5) + 2(-4)}[/tex]
[tex]=\frac{(-3) - 8}{15 +( -8)}[/tex]
[tex]=\frac{-11}{7}[/tex]
≈ 1.57
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Solution #2:
= a - 4b / 3c + 2d
= (-3) - 4(2) / 3(5) + 2(-4)
= (-3) - 8 / 15 + (-8)
= (-3) - 0.53 + (-8)
= (-3.53) + (-8)
= -11.53
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Solution #1 Answer: 1.57
Solution #2 Answer: -11.53
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