Question

A ring of brass has an inner diameter of 5.000 cm when it is at room temperature (20°C). It needs to slip over a pipe with a diameter of 5.005 cm. If the brass ring is heated, it will be able to fit over the pipe. What temperature should the ring be heated to?

Answer 1

Answer:

temperature t2 is  72.63°C

Explanation:

given data

diameter d1 = 5.000 cm

temperature t1 = 20°C

diameter d2 = 5.005 cm

to find out

temperature t2

solution

we will apply here equation of coefficient of linear for brass that is

α = d2 -d1 / d1(t2 -t1)     .........................1

put here all value and find t2

19 × $10^{-6}$ = ( 5.005 - 5 ) / 5( t2 - 20 )

solve it and we get t2

t2 = 20  + 52.63

t2 = 72.63

so temperature t2 is  72.63°C