Question

A 5.4 mW laser beam has its electric field vertical. If it passes through a polarizer with its transmission axis at 60 degree to the vertical, what's the power of the transmitted beam?

2. Polarized light passes through a polarizer, and 70 % gets through. Find the angle between the light's electric field and the polarizer's transmission axis.

Answer 1

Answer:

power 1.35 mw

ANGLE IS 33.27 degree

Explanation:

from Malus law we have following relation

$I = I_0 cos^2\theta$

we know that

power = intensity * area

$A*I_0 cos^2\theta = I*A$

$I = I_0 cos^2\theta$$= 5.4*10^{-3} cos^2{60}$

  = 0.0054*0.25

 = 1.35 mw

2

$I = I_o*cos^2(\theta)$

$\theta = cos^{-1}(\sqrt{(\frac{I}{I_o})}$

= $cos^{-1}(\sqrt{(0.70))}$

$= cos^{-1}(0.836)$

= 33.27 degrees