Question

A bar 2 m long and 25 mm in diameter is subjected to a tensile load of 2 x 10 N/mm^2, calculate the strain energy and modulus of resilience.

Answer 1

Answer:

strain energy=0.049J

modulus of resilience=49.81N/m^2

Explanation

U=N^2LA/(2E)

U=strain energy

L=leght

A=A rea=(pi/4)D^2

E=young Modulus for steel 200.000N/mm^2

N=tensile load

Solving:

U=(20N/mm^2)(2000mm)(pi/4)(25mm)^2/(2*200.000N/mm^2)=49.087Nmm=0.049J

MODULUS Of RESILIENCE

Ω=U/volume

Volume=2x(pi/4)*(0.025)^2=9.817x10-4m^3

Ω=0.049J/9.817x10-4m^3=49.81N/m^2