Help me it’s urgent

Answer:
[tex] a_1 = -\dfrac{3}{4} [/tex]
Step-by-step explanation:
[tex] a_1 \times r = a_2 [/tex]
[tex] a_1 \times r^2 = a_3 [/tex]
[tex] a_1 \times r^3 = a_4 [/tex]
...
[tex] a_1 \times r^8 = a_9 [/tex]
[tex] \dfrac{a_9}{a_4} = \dfrac{a_1 \times r^8}{a_1 \times r^3} = \dfrac{-196}{6} [/tex]
[tex] r^5 = -32 [/tex]
[tex] r = -2 [/tex]
[tex] a_1 \times r^3 = a_4 [/tex]
[tex] a_1 \times (-2)^3 = 6 [/tex]
[tex] a_1 = \dfrac{6}{-8} [/tex]
[tex] a_1 = -\dfrac{3}{4} [/tex]