Answer:
[tex]A=x^2+3x\ un^2.[/tex]
Step-by-step explanation:
The figure consists of two rectangles.
The larger rectangle has the length of (x+4) units and the width of (x-1) units.
The smaller rectangle has the width of (x-(x-1))=(x-x+1)=1 unit and the length of ((x+4)-x)=(x+4-x)=4 units.
The area of the rectangle is
[tex]A_{rectangle}=\text{width}\cdot \text{length}[/tex]
Calculate the area of each rectangle:
[tex]A_{large}=(x-1)(x+4)=x^2 +4x-x-4=x^2 +3x-4\ un^2 .\\ \\A_{small}=1\cdot 4=4\ un^2.[/tex]
So, the area of the whole figure is
[tex]A=A_{large}+A_{small}=x^2+3x-4+4=x^2+3x\ un^2.[/tex]
