Question

the sum of three consecutive odd intergers is 17 less that four the smallest interger?​

Answer 1

Answer:

The integers are 23, 25, 27

Step-by-step explanation:

the sum of three consecutive odd integers

$S = x + (x+2) + (x + 4)$

17 less than four the smallest integer

$S = 4x-17$

Now set them equal and solve

$4x-17 = 3x + 6\\x = 23$