Answer: The concentration of [tex]Ag^+[/tex] ion in the solution is [tex]4.9\times 10^{-11}M[/tex]
Explanation:
The balanced equilibrium reaction for the ionization of calcium fluoride follows:
[tex]AgBr\rightleftharpoons Ag^{+}+Br^-[/tex]
s 0.01
The expression for solubility constant for this reaction will be:
[tex]K_{sp}=[Ag^{+}][Br^-][/tex]
We are given:
[tex]K_{sp}=4.9\times 10^{-13}[/tex]
[tex][Br^-]=0.01M[/tex]
Putting values in above equation, we get:
[tex]4.9\times 10^{-13}=(s)\times 0.01[/tex]
[tex][Ag^+]=4.9\times 10^{-11}M[/tex]
Hence, the concentration of [tex]Ag^+[/tex] ion in the solution is [tex]4.9\times 10^{-11}M[/tex]