Question

An airplane flies eastward and accelerates uniformly. At one position along its path it has a velocity of 28.3 m/s. It then flies a further distance at 43.7 km and its velocity is 50.3 m/s. Find the airplanes acceleration. a) 0.02 m/s^2
b) 0.20 m/s^2
c) 2.00 m/s^2
d) 19.8 m/s^2

Answer 1

Answer:

Acceleration of the airplane, $a=0.02\ m/s^2$

Explanation:

It is given that,

Initial velocity of the airplane, u = 28.3 m/s

Final velocity of the airplane, v = 50.3 m/s

Distance covered, $d=43.7\ km=43.7\times 10^3\ m$

We need to find the acceleration of the airplane. It is given by using third equation of motion as :

$v^2-u^2=2ad$

$a=\dfrac{v^2-u^2}{2d}$

$a=\dfrac{(50.3)^2-(28.3)^2}{2\times 43.7\times 10^3}$

$a=0.0197\ m/s^2$

or

$a=0.02\ m/s^2$

So, the acceleration of the airplane is $0.02\ m/s^2$. Hence, this is the required solution.