.Answer:
491.4 nm
Explanation:
The distance between central and first maxima is,
[tex]y=0.455m[/tex]
And the distance between screen abnd grating is,
[tex]L=1.62 m[/tex]
Now the angle can be find as,
[tex]tan\theta=\frac{y}{L} \\\theta=tan^{-1}(\frac{0.455}{1.62}) \\\theta=15.68^{\circ}[/tex]
Now the grating distance is,
[tex]d=\frac{1}{5500} cm\\d=1.82\times 10^{-6}m[/tex]
Now with m=1 condition will become,
[tex]\lambda=dsin\theta[/tex]
So,
[tex]\lambda=1.82\times 10^{-6}m\times sin(15.68^{\circ})\\\lambda=1.82\times 10^{-6}m\times 0.270\\\lambda=491.4\times 10^{-9}m\\\lambda=491.4 nm[/tex]
Therefore the wavelength of laser light is 491.4 nm.