Question

A student sets up two reactions. Reaction 1 uses 0.240 mol/L of reactant, and Reaction 2 uses 0.560 mol/L of reactant. How many times faster is Reaction 2 compared to Reaction 1?

Answer 1

Answer:

Reaction 2 is 2.333 times faster than reaction 1.

Explanation:

The reaction rate is measured considering the concentration of reactant used or product made and the time interval. This can be expressed in the following equation:

$rate = \frac{[reactant]}{Δtime}$

Therefore, the higher the concentration of reactant used, the faster the reaction will be. If we consider that both Reaction 1 and Reaction 2 happen during the same time interval (Δt), we can express their rates:

$R1 = \frac{[0.240 mol/L]}{Δt}  \\R2 = \frac{[0.560 mol/L}{Δt}$

Dividing R2 per R1:

$\frac{R2}{R1} = \frac{\frac{0.560 mol/L}{Δt} }{\frac{0.240 mol/L}{Δt} } = 2.333$

Thus, Reaction 2 is 2.333 times faster than Reaction 1.