Question

What is the standard enthalpy of formation of CO(g). Given: AH. [C] = -393 kJ mol2. AH [CO] = -283 kJ mol2.

Answer 1

Answer:

The standard enthalpy of formation of CO(g) is:

Δ$H_r_x_n=110kJ mol2$

Explanation:

The chemical equation to formation of CO  is:

$C +\frac{1}{2} O_2$ → $CO$

So, we need to find the standard enthalpy of formation of CO(g) with the expression:

Δ$H_r_x_n=$ΣΔ$H_p_r_o_d_u_c_t_s-$ΣΔ$H_r_e_a_g_e_n_t_s$ (1)

With the information of the exercise we know:

AH [C] = -393 kJ mol2

AH [CO] = -283 kJ mol2

The enthalpy of formation of a pure compound is zero so the enthalpy of Oxygen is zero.

Now, we can replace this values in the equation (1)

Δ$H_r_x_n=-283kJ mol2-(-393 kJ mol2)$

Δ$H_r_x_n=110kJ mol2$