Answer:
207 x 10⁻²³ J
Explanation:
Average kinetic energy per degree of freedom = 1 \ 2 k T
where k is Boltzmann constant and T is absolute temperature
The value of k is 1.38 x 10⁻²³
T given is 100 k
Average kinetic energy of a single degree of freedom
=.5 x 1.38 x 10⁻²³ x 100
= 69 x 10⁻²³
For 3 degree of freedom
Average energy = 3 x 69 x 10⁻²³
207 x 10⁻²³ J
