For this case we must find the value of x of the following equation:
[tex]- (\frac {6} {5} x + 6) +2 = - \frac {4} {5} (- 5x + 7)[/tex]
We eliminate the parentheses taking into account that:
[tex]- * + = -\\- * - = +\\- \frac {6} {5} x-6 + 2 = 4x- \frac {28} {5}[/tex]
We simplify the left side:
[tex]- \frac {6} {5} x-4 = 4x- \frac {28} {5}[/tex]
Add [tex]\frac {28} {5}[/tex]to both sides:
[tex]- \frac {6} {5} x-4 + \frac {28} {5} = 4x[/tex]
Add [tex]\frac {6} {5} x[/tex] to both sides:
[tex]-4+ \frac {28} {5} = 4x + \frac {6} {5} x\\\frac {-20 + 28} {5} =\frac {20x + 6x} {5}\\8 = 26x\\x = \frac {8} {26}\\x = \frac {4} {13}[/tex]
Answer:
[tex]x = \frac {4} {13}[/tex]
