Answer:
[tex]\bigtriangledown.B=0[/tex] is proved.
Explanation:
The magnetic field in the long current carrying wire is,
[tex]B=\frac{\mu_{0}I }{2\pi r } \phi[/tex]
Here, I is the current, B is the magnetic field.
Now, by using cylindrical coordinates for the divergence of B.
[tex]\bigtriangledown.B=\frac{1}{s} \frac{d}{d\phi} B[/tex]
Put the value of B in above equation.
[tex]\bigtriangledown.B=\frac{1}{s} \frac{d}{d\phi}(\frac{\mu_{0}I }{2\pi r } \phi)\\\bigtriangledown.B=0[/tex]
Hence, it is prove that for a long current I carrying wire magnetic field divergence that is [tex]\bigtriangledown.B=0[/tex].