Show explicitly that ▽ . B-0 near a long straight wire carrying a current I. HINT: you may use Cartesian coordinates, but another choice might make it easier

Respuesta :

Answer:

[tex]\bigtriangledown.B=0[/tex] is proved.

Explanation:

The magnetic field in the long current carrying wire is,

[tex]B=\frac{\mu_{0}I }{2\pi r } \phi[/tex]

Here, I is the current, B is the magnetic field.

Now, by using cylindrical coordinates for the divergence of B.

[tex]\bigtriangledown.B=\frac{1}{s} \frac{d}{d\phi} B[/tex]

Put the value of B in above equation.

[tex]\bigtriangledown.B=\frac{1}{s} \frac{d}{d\phi}(\frac{\mu_{0}I }{2\pi r } \phi)\\\bigtriangledown.B=0[/tex]

Hence, it is prove that for a long current I carrying wire magnetic field divergence that is [tex]\bigtriangledown.B=0[/tex].

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