Answer:
The given equation is not correct.
Step-by-step explanation:
It is given that the volume of a sphere is
[tex]V=\frac{\pi d^3}{4}[/tex] .... (1)
where V is the volume and d is the diameter of the sphere.
We need to check whether the equation is dimensionally correct.
We know that the volume of a sphere is
[tex]V_1=\frac{4}{3}\pi r^3[/tex] ... (2)
where, r is radius.
Diameter of sphere is twice of its radius, i.e., d=2r.
Substitute [tex]r=\frac{d}{2}[/tex] in equation (2).
[tex]V_1=\frac{4}{3}\pi (\frac{d}{2})^3[/tex]
[tex]V_1=\frac{4}{3}\pi (\frac{d^3}{2^3})[/tex]
[tex]V_1=\frac{4}{3}\pi (\frac{d^3}{8})[/tex]
[tex]V_1=\frac{1}{6}\pi d^3[/tex]
[tex]V_1\neq V[/tex]
Therefore the given equation is not correct.