Question

Estimate the uncertainty in energy during a time interval of 10-23 s. Express your answer in MeV

Answer 1

Answer:

The uncertainty in energy during a time interval is $2.52375\times10^{-23}\ Mev$

Explanation:

Given that,

Time $\Delta t= 10-23= 13 s$

We need to calculate the uncertainty in energy

Using uncertainty principle

$\Delta E \Delta t \geq \dfrac{\hbar}{2}$

$\Delta E \geq\dfrac{\hbar}{2\Delta t}$

Put the value into the relation

$\Delta E=\dfrac{1.05\times10^{-34}}{2\times13}$

$\Delta E\geq 4.038\times10^{-36}\ J$

$\Delta E\geq \dfrac{4.038\times10^{-36}}{1.6\times10^{-19}}$

$\Delta E\geq 2.52375\times10^{-17}\ ev$

$\Delta E\geq\dfrac{2.52375\times10^{-17}}{10^{6}}\ MeV$

$\Delta E\geq 2.52375\times10^{-23}\ Mev$

Hence, The uncertainty in energy during a time interval is $2.52375\times10^{-23}\ Mev$