Answer:
C) 0.182 W
Explanation:
The effective conductive section is:
[tex]3 * A = 3 * \frac{\pi * d^2}{4} = 3 * \frac{\pi * (0.008 m)^2}{4} = 1.5e-4 m^2[/tex]
The thermal conductivity of stainless steel is
k = 18 w/(m * K)
Heat conduction in a rod follows this equation:
[tex]q = k * A * \frac{(t2 - t1)}{l} = 18 * 1.5e-4 * \frac{(15 - (-190))}{3} = 0.182 W[/tex]