Question

How many grams of sucrose, CiH 2011. must be dissolved in 750 mL of water to prepare a 0.250 molar solution? a. 64.1 g C. 85.5 g e. 96.49 b. 114 g d. 78.2 g

Answer 1

Answer:

a) g C12H22O11 =  64.1 g

Explanation:

[ ] sln = 0.25 mol/L

V sln = 0.750 L

∴ Mw C12H22O11 = 342.3 g/mol

⇒ mol C12H22O11  = 0.25 mol/L * 0.750 L = 0.1875 mol C12H22O11

⇒ g C12H22O11 = 0.1875 mol * 342.3 g/mol

⇒ g C12H22O11 = 64.18 g