Answer:
(D) 0.99 cm
Explanation:
Given that the radius of curvature of the mirror is 25 cm.
And another car is following which is behind the mirror of 20 m.
[tex]u=20m=2000cm[/tex]
Focal length is half of the radius of curvature and it is negative for convex lens.
Now the mirror formula.
[tex]1/v+1/u=1/f[/tex]
So,
[tex]1/v+1/2000=-1/(25/2)\\1/v=-1/2000-1/12.5\\v=-12.422cm[/tex]
Now
Magnification is,
[tex]m=-v/u[/tex]
So,
[tex]m=12.422/2000=0.00621[/tex]
So, Height of the image
[tex]mh=0.00621\times 1.6 m\\mh=0.0099m\\mh=0.99cm[/tex]
Therefore, the image height is 0.99 cm.