Answer:
[tex]n=40[/tex]
Explanation:
We want to know the value of [tex]n[/tex] when [tex]P=480[/tex]
[tex]P=3n^2-90n-720\\480=3n^2-90n-720\\3n^2-90n-720-480=0\\3n^2-90n-1200=0\\3(n^2-30n-400)=0\\n^2-30n-400=0[/tex]
From here, we can find the factors of the quadratic equation, we need two numbers that multiplied give -400 and added -30. Since they are factors of 400, we can choose -20x20 or -40x10. When adding -20 and 20 the result is zero, but the sum of -40 and 10 is -30. Then:
[tex]n^2-30n-400=0\\(n-40)(n+10)=0\\[/tex]
The solutions of the quadratic equation are[tex]n-40=0[/tex] and [tex]n+10=0[/tex]:
[tex]n_1=40\\n_2=-10[/tex]
Since [tex]n[/tex] is a positive integer:
[tex]n=40[/tex]