Respuesta :
Answer:
C) In[reactant] vs. time
Explanation:
For a first order reaction the integrated rate law equation is:
[tex]A = A_{0}e^{-kt}[/tex]
where A(0) = initial concentration of the reactant
A = concentration after time 't'
k = rate constant
Taking ln on both sides gives:
[tex]ln[A] = ln[A]_{0}-kt[/tex]
Therefore a plot of ln[A] vs t should give a straight line with a slope = -k
Hence, ln[reactant] vs time should be plotted for a first order reaction.
The data that should be plotted to show that experimental concentration data fits a first-order reaction is: C. In [reactant] vs. time.
What is a first-order reaction?
A first-order reaction can be defined as a type of chemical reaction in which the reaction rate (rate of reaction) is directly proportional to the concentration of the reacting chemical substance or elements.
Mathematically, the integrated rate law equation for a first-order reaction is given by this formula:
[tex]A=A_o e^{kt}[/tex]
Where:
- A is the concentration after time (t).
- [tex]A_o[/tex] is the initial concentration of the reactant.
- t is the time.
- k is the rate constant.
Taking the ln of both sides, we have:
[tex]ln(A)=ln(A_o)-kt[/tex]
Therefore, the data that should be plotted to show that experimental concentration data fits a first-order reaction is In[reactant] versus time.
Read more on rate constant here: brainly.com/question/24749252