Question

The density of silver is 10.5 g/cm^3. What is the volume of a piece of Ag that contains 2.8 × 10^22 atoms?

Answer 1

Answer:

0.4777 cm³

Explanation:

Molar mass is defined as the mass of 1 mole of the substance.  

The molar mass fo Ag is 107.8682 g/mol

Since, 1 mole of Ag contains 6.022×10²³ molecules of Ag

So,  

6.022×10²³ molecules of Ag has a mass of 107.8682 g

Also,  

1 molecule of Ag has a mass of 107.8682/6.022×10²³  g

2.8×10²² molecules of Ag has a mass of (107.8682/6.022×10²³)×2.8×10²²  g

Mass of 2.8×10²² molecules = 5.0155 g

Given that density = 10.5 g/cm³

Volume = ?

So, volume:  

$Volume=\frac {Mass}{Density}$  

$Volume=\frac {5.0155}{10.5}\ cm^3$  

Volume = 0.4777 cm³