Question

A uniform solid sphere of radius r = 0.510 m and mass m = 15.5 kg turns counterclockwise about a vertical axis through its center (when viewed from above), at an angular speed of 3.20 rad/s. What is its vector angular momentum about this axis? (Enter the magnitude in kg · m2/s.)

Answer 1

Answer:

5.160384 kg*m²/s

Explanation:

The vector angular momentum P can be found using the following expression:

P = I * w

I refers to the inertia, that for a sphere is found using the expression:

I = $\frac{2}{5}$ * m * r² = $\frac{2}{5}$ * 15.5kg * (0.510m)² = 1.61262 kg*m².

The angular velocity w is given by the problem, and has a value of 3.2 rad/s.

Replacing the data we get:

P = 1.61262 kg*m² * 3.2 rad/s = 5.160384 kg*m²/s