Question

Soil in a forest with a bulk density of 1.1 Mg/m3 contains 100 parts per million of salt. How many pounds of salt are contained in the top 6 inches of 1 acre of this soil?

Answer 1

Answer:

The amount of salt are 159.56 pounds.

Explanation:

The volume of soil in top 6 inches in an area of 1 acre is calculated as

$Volume = Depth\times Area\\\\V=\frac{6}{39.37}\times 1\times 4046.86m^{2}\\\\V=616.74m^{3}$

Since it is given that 1 cubic meter of the soil has a weight of 1100 kg thus 616.74 cubic meters of soil shall have a mass of 616.74 x 1100 = 678414 kg

Since it is given that 1 kg of the soil shall have 100 milligrams of the salt thus 678414 kg shall have 678414 x 100 milligrams of salt

Thus the amount of salt in the given volume  of soil  shall be 67.8414 kilograms.

Thus the mass in pounds shall be 2.205 x 67.8414 kg =149.56 pounds