Answer:
Part 1) [tex]a_n=2+5(n-1)[/tex]
Part 2) The sum of the first 30 terms is 2,235
Step-by-step explanation:
Part 1) write an explicit formula for the nth term
we know that
In an Arithmetic Sequence the difference between one term and the next is a constant, and this constant is called the common difference
We can write an Arithmetic Sequence as a rule:
[tex]a_n=a_1+d(n-1)[/tex]
where
[tex]a_n[/tex] is the nth term
[tex]a_1[/tex] is the first term
n is the number of terms
d is the common difference
we have the sequence
[tex]2,7,12,...[/tex]
we have
[tex]a_1=2[/tex], [tex]a_2=7[/tex], [tex]a_3=12[/tex]
Find the common difference d
[tex]a_2-a_1=7-2=5[/tex]
[tex]a_3-a_2=12-7=5[/tex]
The common difference is d=5
substitute in the formula
[tex]a_n=2+5(n-1)[/tex]
Part 2) Find the sum of the first 30 terms
we know that
The formula to calculate the sum of an arithmetic sequence is
[tex]S=\frac{n}{2}(2a_1+(n-1)d)[/tex]
where
[tex]a_1[/tex] is the first term
n is the number of terms
d is the common difference
we have
[tex]a_1=2[/tex]
[tex]d=5[/tex]
[tex]n=30[/tex]
substitute
[tex]S=\frac{30}{2}(2(2)+(30-1)5)[/tex]
[tex]S=2,235[/tex]