Given the sequence 2,7,12,..., write an explicit
formula for the nth term, assuming a1=2.
2 Given the sequence 2,7,12,..., find the sum of
the first 30 terms

Respuesta :

Answer:

Part 1) [tex]a_n=2+5(n-1)[/tex]

Part 2) The sum of  the first 30 terms is 2,235

Step-by-step explanation:

Part 1)  write an explicit  formula for the nth term

we know that

In an Arithmetic Sequence the difference between one term and the next is a constant, and this constant is called the common difference

We can write an Arithmetic Sequence as a rule:

[tex]a_n=a_1+d(n-1)[/tex]

where

[tex]a_n[/tex] is the nth term

[tex]a_1[/tex] is the first term

n is the number of terms

d is the common difference

we have the sequence

[tex]2,7,12,...[/tex]

we have

[tex]a_1=2[/tex], [tex]a_2=7[/tex], [tex]a_3=12[/tex]

Find the common difference d

[tex]a_2-a_1=7-2=5[/tex]

[tex]a_3-a_2=12-7=5[/tex]

The common difference  is d=5

substitute in the formula

[tex]a_n=2+5(n-1)[/tex]

Part 2) Find the sum of  the first 30 terms

we know that

The formula to calculate the sum of an arithmetic sequence is

[tex]S=\frac{n}{2}(2a_1+(n-1)d)[/tex]

where

[tex]a_1[/tex] is the first term

n is the number of terms

d is the common difference

we have

[tex]a_1=2[/tex]

[tex]d=5[/tex]

[tex]n=30[/tex]

substitute

[tex]S=\frac{30}{2}(2(2)+(30-1)5)[/tex]

[tex]S=2,235[/tex]

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