A NASA explorer spacecraft with a mass of 1,000 kg takes off in a positive direction from a stationary asteroid. If the velocity of the spacecraft is 250 m/s and the asteroid is pushed back –25 m/s, what is the mass of the asteroid? Assume there is no net force on the system.

Respuesta :

Answer: 10000 kg

Explanation:

The momentum [tex]p[/tex] is given by the following equation:  

[tex]p=m.V[/tex] (1)  

Where:  

[tex]m[/tex] is the mass of the object  

[tex]V[/tex] is the velocity of the object

Now, in this case and according the conservation of momentum:

[tex]m_{1}v_{1}+m_{2}v_{2}=m_{1}u_{1}+m_{2}u_{2}[/tex]   (2)  

Where:

[tex]m_{1}=1000kg[/tex] is the mass of the spacecraft

[tex]m_{2}[/tex] is the mass of the asteroid

[tex]v_{1}=0[/tex] is the initial velocity of the spacecraft

[tex]v_{2}=0[/tex] is the initial velocity of the asteroid (because we are told the asteroid is stationary, as the spacracft is on the sateroid it remains stationary as well)

[tex]u_{1}=250m/s[/tex] is the final velocity of the spacecraft

[tex]u_{2}=-25m/s[/tex] is the final velocity of the asteroid

Rewritting (2):

[tex]0=m_{1}u_{1}+m_{2}u_{2}[/tex]   (3)  

[tex]0=(1000kg)(250m/s)+m_{2}(-25m/s)[/tex]   (4)  

Finding [tex]m_{2}[/tex]:

[tex]m_{2}=10000kg[/tex] This is the mass of the asteroid

Answer:

Option C 10,000 kg

Explanation:

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