Step-by-step explanation:
the function [tex]f(n) = \frac{3n +1 }{n}[/tex] equals 3 only in [tex]x = \infty[/tex] and [tex]x = -\infty[/tex].
Prove:
[tex]\lim\limits_{n \to \pm\infty} \frac{3n +1}{n} = \lim\limits_{n \to \pm\infty} \left(\frac{3n}{n} + \frac{1}{n}\right)[/tex]
then
[tex]\lim\limits_{n \to \pm\infty} \left(\frac{3\not{n}}{\not{n}} + \frac{1}{n}\right) = \lim\limits_{n \to \pm\infty} 3 + \frac{1}{n} [/tex]
and
[tex]\lim\limits_{n \to \pm\infty} 3 + \not{\frac{1}{n}^0} = 3[/tex]