Question

A horizontal force of 750 N is needed to overcome the force of static friction between a level floor and a 250-kg crate. If g-9.8 m/s, what is the coefficient of static friction? a. 3.0 b. 0.15 c. 0.28 d. 0.31

Answer 1

Answer:

0.31

Explanation:

horizontal force, F = 750 N

mass of crate, m = 250 kg

g = 9.8 m/s^2

The friction force becomes applied force = 750 N

According to the laws of friction,

Friction force = μ x Normal reaction of the surface

here, μ be the coefficient of friction

750 = μ x m g

750 = μ x 250 x 9.8

μ = 0.31

Thus, the coefficient of static friction is 0.31.

Answer 2

Based on the calculatins, the coefficient of static friction is equal to: D. 0.31.

Given the following data:

Force = 750 Newton.

Mass = 250 kg.

Acceleration due to gravity = 9.8 $m/s^2$

How to calculate the coefficient of static friction.

Mathematically, the static frictional force acting on an object is giving by this formula:

$F_s=\mu N=\mu mg\\\\\mu =\frac{F_s}{mg}$

Where:

• $\mu$ is the coefficient of static friction.

• N is the normal force.

• m is the mass.

• g is the acceleration due to gravity.

Substituting the given parameters into the formula, we have;

$\mu =\frac{750}{250 \times 9.8}\\\\\mu =0.31$

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