Question

a bag contains 6 red marbles 4 blue marbles 7 green marbles and 3 yellow marbles a marble is drawn from the bag and is not replaced then a second ball is drawn what is the probability that both marbles drawn were red

Answer 1

Answer:  $\bold{\dfrac{3}{38}=7.9\%}$

Step-by-step explanation:

There are 20 total marbles and 6 of them are red.

The first draw has a probability of 6 red out 20 total marbles.

The second draw has a probability of 5 remaining red out of 19 remaining marbles

1st draw    and      2nd draw

   $\dfrac{6}{20}$           ×              $\dfrac{5}{19}$          $=\dfrac{30}{380}\qquad =\dfrac{3}{38}\qquad =7.9\%$