Alejandra correctly wrote the equation y – 3 = y minus 3 equals StartFraction 1 Over 5 EndFraction left-parenthesis x minus 10 right-parenthesis.(x – 10) to represent a line that her teacher sketched. The teacher then changed the line so it had a slope of 2, but still went through the same point. Which equation should Alejandra write to represent the new line?

y – 6 = 2(x – 10)
y – 2 = y minus 2 equals StartFraction 1 Over 5 EndFraction left-parenthesis x minus 10 right-parenthesis.(x – 10)
y – 3 = y minus 3 equals StartFraction 1 Over 5 EndFraction left-parenthesis x minus 2 right-parenthesis.(x – 2)
y – 3 = 2(x – 10)

Respuesta :

Answer:

  y – 3 = 2(x – 10)

Step-by-step explanation:

In point-slope form, the equation is written ...

  y -k = m(x -h) . . . . . . . for line with slope m through point (h, k)

If only the slope changes, only the value just outside parentheses changes. When the point is (10, 3) and the new slope is 2, the new equation is ...

  y -3 = 2(x -10)

The new equation which Alejandra should write is; y – 3 = 2(x – 10).

Slope form of the Equation of a straight line

According to the task content;

  • It follows that the initial equation is; y -3 = 1/5(x-10)

On this note, it follows from comparison with the the equation; (y-a) = m(x-b) that the slope of the equation is; 1/5.

On this note, when the slope is 2, then the new equation is; y – 3 = 2(x – 10).

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