Question

Find three consecutive even integers, such that
5 times of first integer is 18 more than the sum
of second and third integers.

Answer 1

Answer:

8,10 ,12

Step-by-step explanation:

x

x+2

x+4

    5x-18 =x+2 + x+4

5x-18=2x+6

3x=24

x=8

   8*5=40   40-18= 22

   10+12 = 22