Question

A finch rides on the back of a galapagos tortoise, which walks at the stately pace of 0.060 m/s. after 1.0 minutes the finch tires of the tortoise's slow pace, and takes flight in the same direction for another 1.3 minutes at 12 m/s

Answer 1

Answer:

The average speed is $6.809\ m/sec$

Explanation:

The question is

What was the average speed of the finch for this 2.3-minute interval?

we know that

To determine the average speed divide the total distance by the total time

Let

x ----> the total distance in meters

y ----> the total time in seconds

s ----> average speed in m/sec

so

$s=\frac{x}{y}$

step 1

Find the total distance x

To find the distance multiply the speed by the time

For the first 1.0 minutes

1 minute=60 sec

x=0.060(60)=3.6 m

For the other 1.3 minutes

1 minute=60 sec

x=12(60*1.3)=936 m

the total distance is

x=3.6+936=939.6 m

step 2

Find the total time y

y=(1+1.3)(60)=138 sec

step 3

Find the average speed

$s=\frac{x}{y}$

substitute the values

$s=\frac{939.6}{138}=6.809\ m/sec$