Answer:
V= 112.68 m/s
[tex]P_1=78.48 KPa[/tex]
Explanation:
Given that
Diameter of pipe = 150 mm
Diameter of nozzle = 50 mm
We know that the velocity of water at the exit of tank will be
[tex]U=\sqrt{2gh}[/tex]
Now by putting the values
[tex]U=\sqrt{2gh}[/tex]
[tex]U=\sqrt{2\times 9.81\times 8}[/tex] (here h= 8m)
U= 12.52 m/s
Lets take velocity of fluid at the exit of nozzle is V
So from continuity equation
[tex]\dfrac{\pi}{4}150^2\times U=\dfrac{\pi}{4}50^2\times V[/tex]
So V= 9 U
V= 9 x 12.52 m/s
V= 112.68 m/s
To find pressure in the pipe
[tex]P_1=1000\times 9.81\times 8\ Pa[/tex]
[tex]P_1=78.48 KPa[/tex]