Answer:
The minimum diameter of other platform is 3.162 meters.
Explanation:
We shall use Principle of transmission of pressure to solve the problem
The Principle of transmission of pressure states that any increase in pressure in a fluid is increased throughout the whole fluid
Mathematically we have
Increase in pressure due to person of mass 100 kg standing on a platform of diameter 1 meter equals
[tex]P_{1}=\frac{F}{Area}=\frac{mg}{\frac{\pi}{4}d_{1}^{2}}\\\\\therefore P_{1}=\frac{4\times 100\times g}{\pi \times (1)^{2}}...............(i)[/tex]
The increase in pressure shall be equal to the pressure applied to the car
Thus to just raise the car we have
[tex]P_{1}\times A_{2}=W_{car}[/tex]
where
[tex]A_{2}[/tex] is the area of platform 2
thus equating the values we get
[tex]\frac{4\times 1000\times g }{\pi \times d^{2}}=\frac{4\times 100\times g}{\pi \times 1^{2}}\\\\\therefore d^{2}=10\\\\\therefore d=\sqrt{10}=3.162meters[/tex]
