Question

Lithium and nitrogen react to produce lithium nitride: 6Li + N2 --> 2Li3N How many moles of N2 are needed to react with 0.500 mol of Lithium?

Answer 1

The number of moles of $N_2$ that is required for reacting with the  0.500 mol of Lithium is 0.0833 moles.

• According to the given equation:

6 moles → 1 moleN_2

0.500 mol → X

So,

0.500 × 1  = 6x

x = 0.0833 moles

Therefore we can conclude that the number of moles of $N_2$ that is required for reacting with the  0.500 mol of Lithium is 0.0833 moles.

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