I need to find the slope of this. Can someone help?

[tex]\bf (\stackrel{x_1}{20}~,~\stackrel{y_1}{30})\qquad (\stackrel{x_2}{80}~,~\stackrel{y_2}{60}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{60}-\stackrel{y1}{30}}}{\underset{run} {\underset{x_2}{80}-\underset{x_1}{20}}}\implies \cfrac{30}{60}\implies \cfrac{1}{2}[/tex]
Answer:
[tex]\frac{1}{2}[/tex]
Step-by-step explanation:
Hello, I think I can help you with this
In mathematics is called a slope to the inclination of a linear, natural or constructive element with respect to the horizontal.with two known points P1 and P2 it can be calculated using
[tex]slope=\frac{y_{2}-y_{1} }{x_{2}-x_{1}}\\ where \\P1(x_{1},y_{1})\\P2(x_{2},y_{2})[/tex]
Step 1
based on the graph
Let
P1(0,20)
P2(40,40)
put the values into the formula
[tex]slope=\frac{y_{2}-y_{1} }{x_{2}-x_{1}}\\slope=\frac{40-20 }{40-0}\\slope=\frac{20}{40} \\slope=\frac{1}{2}\\[/tex]
Have a great day.