The formula for a directed line is:
X = K1(X2) + (K2(X1) / K3
Y = K1(Y2) + (K2(Y1) / K3
K1 = numerator = 2
K2 = denominator - numerator = 3-2 = 1
K3 = denominator = 3
X = (2(6) + 1(3)) /3
X = (12+3) / 3
X = 12/3
X = 5
Y = (2(11) + 1(2)) /3
Y = (22 + 2) /3
Y = 24/3
Y = 8
The point is (5,8)
Answer:
[tex](\frac{21}{5} ,\frac{28}{5} )[/tex] is the point
Step-by-step explanation:
A(3, 2) and B(6, 11)
The ratio that divided AB is 2:3
we use section formula
2:3 is m:n
formula is [tex](\frac{mx_2+nx_1}{m+n} ,\frac{my_2+ny_1}{m+n} )[/tex]
A(3, 2) is (x1,y1) and B(6, 11) is (x2,y2)
Plug in the value in the formula
[tex](\frac{mx_2+nx_1}{m+n} ,\frac{my_2+ny_1}{m+n} )[/tex]
[tex](\frac{(2)(6)+3(3)}{2+3} ,\frac{2(11)+3(2)}{2+3} )[/tex]
[tex](\frac{21}{5} ,\frac{28}{5} )[/tex]
