Answer :
(a) The number of oxygen molecules present in 0.100 mL of gas is, [tex]2.688\times 10^{18}[/tex]
(b) The number of oxygen molecules present in 1.0 L of gas is, [tex]2.688\times 10^{22}[/tex]
(c) The volume of oxygen gas is, [tex]3.719\times 10^{-20}mL[/tex]
Explanation :
(a) To calculate the number of oxygen molecules present in 0.100 mL of gas.
As, 22400 mL of oxygen gas contains [tex]6.022\times 10^{23}[/tex] number of oxygen molecules
So, 0.100 mL of oxygen gas contains [tex]\frac{0.100}{22400}\times 6.022\times 10^{23}=2.688\times 10^{18}[/tex] number of oxygen molecules
(b) To calculate the number of oxygen molecules present in 1.00 L or 1000 mL of gas.
As, 22400 mL of oxygen gas contains [tex]6.022\times 10^{23}[/tex] number of oxygen molecules
So, 1000 mL of oxygen gas contains [tex]\frac{1000}{22400}\times 6.022\times 10^{23}=2.688\times 10^{22}[/tex] number of oxygen molecules
(c) To calculate the volume of oxygen gas for one molecule of oxygen.
As, [tex]6.022\times 10^{23}[/tex] number of oxygen molecules present in 22400 mL of oxygen gas
So, 1 oxygen molecules present in [tex]\frac{1}{6.022\times 10^{23}}\times 22400mL=3.719\times 10^{-20}mL[/tex] of oxygen gas