Respuesta :

@Tarynalycee

Did you finish the Precal test yet? If you did, may you be so kind as to let me know of the answers? I am so desperate and I saw your questions as a sign of help.

For f(x) and g(x) to be inverse functions, then [tex]f(g(x)) = x[/tex]

f(x) and g(x) are not inverse functions

The functions are given as:

[tex]f(x) = \frac{5x + 1}{x}[/tex]

[tex]g(x) = \frac x{5x + 1}[/tex]

We have:

[tex]f(x) = \frac{5x + 1}{x}[/tex]

Substitute g(x) for x

[tex]f(g(x)) = \frac{5g(x) + 1}{g(x)}[/tex]

Substitute [tex]g(x) = \frac x{5x + 1}[/tex]

[tex]f(g(x)) = \frac{5 \times \frac x{5x + 1} + 1}{\frac x{5x + 1}}[/tex]

[tex]f(g(x)) = \frac{\frac{5x}{5x + 1} + 1}{\frac x{5x + 1}}[/tex]

Take LCM

[tex]f(g(x)) = \frac{\frac{5x + 5x + 1}{5x + 1}}{\frac x{5x + 1}}[/tex]

Cancel out 5x + 1

[tex]f(g(x)) = \frac{5x + 5x + 1}{x}[/tex]

[tex]f(g(x)) = \frac{10x + 1}{x}[/tex]

Recall that, the condition is:

[tex]f(g(x)) = x[/tex]

This means that: f(x) and g(x) are not inverse functions

Read more about inverse functions at:

https://brainly.com/question/10300045

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