Respuesta :
@Tarynalycee
Did you finish the Precal test yet? If you did, may you be so kind as to let me know of the answers? I am so desperate and I saw your questions as a sign of help.
For f(x) and g(x) to be inverse functions, then [tex]f(g(x)) = x[/tex]
f(x) and g(x) are not inverse functions
The functions are given as:
[tex]f(x) = \frac{5x + 1}{x}[/tex]
[tex]g(x) = \frac x{5x + 1}[/tex]
We have:
[tex]f(x) = \frac{5x + 1}{x}[/tex]
Substitute g(x) for x
[tex]f(g(x)) = \frac{5g(x) + 1}{g(x)}[/tex]
Substitute [tex]g(x) = \frac x{5x + 1}[/tex]
[tex]f(g(x)) = \frac{5 \times \frac x{5x + 1} + 1}{\frac x{5x + 1}}[/tex]
[tex]f(g(x)) = \frac{\frac{5x}{5x + 1} + 1}{\frac x{5x + 1}}[/tex]
Take LCM
[tex]f(g(x)) = \frac{\frac{5x + 5x + 1}{5x + 1}}{\frac x{5x + 1}}[/tex]
Cancel out 5x + 1
[tex]f(g(x)) = \frac{5x + 5x + 1}{x}[/tex]
[tex]f(g(x)) = \frac{10x + 1}{x}[/tex]
Recall that, the condition is:
[tex]f(g(x)) = x[/tex]
This means that: f(x) and g(x) are not inverse functions
Read more about inverse functions at:
https://brainly.com/question/10300045