Question

please help me !!!!!!!



1.Calculate the end velocity of a rocket that traveled 16km in 2 seconds.

distance

time



2.Calculate the rockets acceleration m with a start velocity of 0m/s and the end velocity from #1 for 10 seconds.



(final velocity- start velocity)

time



* Be sure to include units!

Answer 1

Hi, the answer to number one was 8 so...

8/10 = 0.8

You're from k12 right? :)

Answer 2

Explanation:

1. Distance covered by the rocket, $d=16\ km=16\times 10^3\ m$

Time taken, t = 2 s

The velocity of rocket is given by:

$v=\dfrac{d}{t}$

$v=\dfrac{16\times 10^3\ m}{2\ s}$  

v = 8000 m/s

So, the velocity of a rocket is 8000 m/s.

2. Starting velocity of the rocket, u = 0

Final velocity, v = 8000 m/s

Time taken, t = 10 s

Change in speed, (v-u) = 8000 m/s

Acceleration of rocket is given by :

$a=\dfrac{v-u}{t}$

$a=\dfrac{8000\ m/s}{10\ s}$

$a=800\ m/s^2$

So, the acceleration of the rocket is $800\ m/s^2$. Hence, this is the required solution.