Answer:
AFC = [tex]\frac{TFC}{q}[/tex]
MC = [tex]\frac{d}{dq}[/tex] TC
AVC = [tex]\frac{TVC}{q}[/tex]
AC = [tex]\frac{TC}{q}[/tex]
Explanation:
The cost function is given as [tex]C=9+q^{2}[/tex].
The fixed cost here is 9, it will not be affected by the level of output.
The variable cost is [tex]q^{2}[/tex].
AFC = [tex]\frac{9}{q}[/tex]
MC = [tex]\frac{d}{dq}[/tex] TC
MC = [tex]\frac{d}{dq}[/tex] [tex]C=9+q^{2}[/tex]
MC = 2q
AVC = [tex]\frac{TVC}{q}[/tex]
AVC = [tex]\frac{q^2}{q}[/tex]
AVC = q
AC = [tex]\frac{TC}{q}[/tex]
AC = [tex]\frac{[tex]C=9+q^{2}[/tex]}{q}[/tex]
AC = [tex]\frac{9}{q} +q[/tex]
